📚 mention how to get a node's path

Thanks to @arielger for mentioning this and @jschroeter for posting a solution!

Author: ngryman

readme.md

@@ -84,6 +84,26 @@ crawl(tree, (node, context) => {
 })
 ```
 
+## FAQ
+
+### How can I get the path of the current node ([#37](https://github.com/ngryman/tree-crawl/issues/37))?
+
+**tl;dr It's easy for DFS, less easy for BFS**
+
+If you are using DFS you can use the following utility function:
+```
+const = getPath(context) =>
+  context.cursor.stack.xs.reduce((path, item) => {
+    if (item.node) {
+      path.push(item.node)
+    }
+    return path
+  })
+```
+If you are really concerned about performance, you could read items from the stack directly. Each item has a `node` and `index` property that you can use. The first item in the stack can be discarded and will have a `node` set to `null`. Be aware that you should not mutate the stack, or it will break the traversal.
+
+If you are using BFS, things gets more complex. A *simple hacky* way to do so is to traverse the tree using DFS first. You can ad a `path` property to your nodes using the method above. And then do your regular BFS traversal using that `path` property.
+
 ## API
 
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