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API: Change default for Index.union sort #25007

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28 changes: 26 additions & 2 deletions doc/source/whatsnew/v0.24.1.rst
Original file line number Diff line number Diff line change
Expand Up @@ -15,10 +15,34 @@ Whats New in 0.24.1 (February XX, 2019)
These are the changes in pandas 0.24.1. See :ref:`release` for a full changelog
including other versions of pandas.

.. _whatsnew_0241.api:

API Changes
~~~~~~~~~~~

Changing the ``sort`` parameter for :meth:`Index.Union`
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

The default ``sort`` value for :meth:`Index.union` has changed from ``True`` to ``None``.
The default *behavior* remains the same: The result is sorted, unless

1. ``self`` and ``other`` are identical
2. ``self`` or ``other`` is empty
3. ``self`` or ``other`` contain values that can not be compared (a ``RuntimeWarning`` is raised).

This allows ``sort=True`` to now mean "always sort" A ``TypeError`` is raised if the values cannot be compared.

Changed the behavior of :meth:`Index.intersection` with ``sort=True``
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

When ``sort=True`` is provided to :meth:`Index.intersection`, the values are always sorted. In 0.24.0,
the values would not be sorted when ``self`` and ``other`` were identical. Pass ``sort=False`` to not
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I am -1 on this change. We do NOT do this elsewhere, e.g. .reindex, so this is extra useless sorting. (basically cases 1 and 2 above). I am not sure of the utility of 3 at all. We cannot guarantee sorting, showing a warning is fine ; this has been this way since pandas inception. I don't see any utility in changing this.

sort the values.
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Maybe we should make it clearer that this was new behaviour in 0.24.0, and that no behaviour changed compared to what you could do on 0.23 ?


.. _whatsnew_0241.regressions:

Fixed Regressions
^^^^^^^^^^^^^^^^^
~~~~~~~~~~~~~~~~~

- Bug in :meth:`DataFrame.itertuples` with ``records`` orient raising an ``AttributeError`` when the ``DataFrame`` contained more than 255 columns (:issue:`24939`)
- Bug in :meth:`DataFrame.itertuples` orient converting integer column names to strings prepended with an underscore (:issue:`24940`)
Expand All @@ -27,7 +51,7 @@ Fixed Regressions
.. _whatsnew_0241.enhancements:

Enhancements
^^^^^^^^^^^^
~~~~~~~~~~~~


.. _whatsnew_0241.bug_fixes:
Expand Down
5 changes: 4 additions & 1 deletion pandas/_libs/lib.pyx
Original file line number Diff line number Diff line change
Expand Up @@ -233,11 +233,14 @@ def fast_unique_multiple(list arrays, sort: bool=True):
if val not in table:
table[val] = stub
uniques.append(val)
if sort:
if sort is None:
try:
uniques.sort()
except Exception:
# TODO: RuntimeWarning?
pass
elif sort:
uniques.sort()

return uniques

Expand Down
50 changes: 41 additions & 9 deletions pandas/core/indexes/base.py
Original file line number Diff line number Diff line change
Expand Up @@ -2245,18 +2245,34 @@ def _get_reconciled_name_object(self, other):
return self._shallow_copy(name=name)
return self

def union(self, other, sort=True):
def union(self, other, sort=None):
"""
Form the union of two Index objects.

Parameters
----------
other : Index or array-like
sort : bool, default True
Sort the resulting index if possible
sort : bool or None, default None
Whether to sort the resulting Index.

* None : Sort the result, except when

1. `self` and `other` are equal.
2. `self` or `other` has length 0.
3. Some values in `self` or `other` cannot be compared.
A RuntimeWarning is issued in this case.

* True : sort the result. A TypeError is raised when the
values cannot be compared.
* False : do not sort the result.

.. versionadded:: 0.24.0

.. versionchanged:: 0.24.1

Changed the default `sort` to None, matching the
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why is this being changed? this is certainly not a regression at all. This was the default behavior.

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To be clear: no behaviour is changed. It was indeed the default, it stays the default. It's only the value that encodes the default that is changed (True -> None), so that True can mean something else (=always sort).

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ok, maybe it should be more clear in the doc-string

behavior of pandas 0.23.4 and earlier.

Returns
-------
union : Index
Expand All @@ -2273,10 +2289,16 @@ def union(self, other, sort=True):
other = ensure_index(other)

if len(other) == 0 or self.equals(other):
return self._get_reconciled_name_object(other)
result = self._get_reconciled_name_object(other)
if sort:
result = result.sort_values()
return result

if len(self) == 0:
return other._get_reconciled_name_object(self)
result = other._get_reconciled_name_object(self)
if sort:
result = result.sort_values()
return result

# TODO: is_dtype_union_equal is a hack around
# 1. buggy set ops with duplicates (GH #13432)
Expand Down Expand Up @@ -2319,13 +2341,16 @@ def union(self, other, sort=True):
else:
result = lvals

if sort:
if sort is None:
try:
result = sorting.safe_sort(result)
except TypeError as e:
warnings.warn("{}, sort order is undefined for "
"incomparable objects".format(e),
RuntimeWarning, stacklevel=3)
elif sort:
# raise if not sortable.
result = sorting.safe_sort(result)

# for subclasses
return self._wrap_setop_result(other, result)
Expand All @@ -2342,8 +2367,12 @@ def intersection(self, other, sort=False):
Parameters
----------
other : Index or array-like
sort : bool, default False
Sort the resulting index if possible
sort : bool or None, default False
Whether to sort the resulting index.

* False : do not sort the result.
* True : sort the result. A TypeError is raised when the
values cannot be compared.

.. versionadded:: 0.24.0

Expand All @@ -2367,7 +2396,10 @@ def intersection(self, other, sort=False):
other = ensure_index(other)

if self.equals(other):
return self._get_reconciled_name_object(other)
result = self._get_reconciled_name_object(other)
if sort:
result = result.sort_values()
return result

if not is_dtype_equal(self.dtype, other.dtype):
this = self.astype('O')
Expand Down
30 changes: 26 additions & 4 deletions pandas/core/indexes/multi.py
Original file line number Diff line number Diff line change
Expand Up @@ -2879,18 +2879,34 @@ def equal_levels(self, other):
return False
return True

def union(self, other, sort=True):
def union(self, other, sort=None):
"""
Form the union of two MultiIndex objects

Parameters
----------
other : MultiIndex or array / Index of tuples
sort : bool, default True
Sort the resulting MultiIndex if possible
sort : bool or None, default None
Whether to sort the resulting Index.

* None : Sort the result, except when

1. `self` and `other` are equal.
2. `self` has length 0.
3. Some values in `self` or `other` cannot be compared.
A RuntimeWarning is issued in this case.

* True : sort the result. A TypeError is raised when the
values cannot be compared.
* False : do not sort the result.

.. versionadded:: 0.24.0

.. versionchanged:: 0.24.1

Changed the default `sort` to None, matching the
behavior of pandas 0.23.4 and earlier.

Returns
-------
Index
Expand All @@ -2901,8 +2917,12 @@ def union(self, other, sort=True):
other, result_names = self._convert_can_do_setop(other)

if len(other) == 0 or self.equals(other):
if sort:
return self.sort_values()
return self

# TODO: Index.union returns other when `len(self)` is 0.

uniq_tuples = lib.fast_unique_multiple([self._ndarray_values,
other._ndarray_values],
sort=sort)
Expand All @@ -2917,7 +2937,7 @@ def intersection(self, other, sort=False):
Parameters
----------
other : MultiIndex or array / Index of tuples
sort : bool, default True
sort : bool, default False
Sort the resulting MultiIndex if possible

.. versionadded:: 0.24.0
Expand All @@ -2934,6 +2954,8 @@ def intersection(self, other, sort=False):
other, result_names = self._convert_can_do_setop(other)

if self.equals(other):
if sort:
return self.sort_values()
return self

self_tuples = self._ndarray_values
Expand Down
59 changes: 56 additions & 3 deletions pandas/tests/indexes/multi/test_set_ops.py
Original file line number Diff line number Diff line change
Expand Up @@ -203,10 +203,16 @@ def test_union(idx, sort):

# corner case, pass self or empty thing:
the_union = idx.union(idx, sort=sort)
assert the_union is idx
if sort:
tm.assert_index_equal(the_union, idx.sort_values())
else:
assert the_union is idx

the_union = idx.union(idx[:0], sort=sort)
assert the_union is idx
if sort:
tm.assert_index_equal(the_union, idx.sort_values())
else:
assert the_union is idx

# won't work in python 3
# tuples = _index.values
Expand Down Expand Up @@ -238,7 +244,10 @@ def test_intersection(idx, sort):

# corner case, pass self
the_int = idx.intersection(idx, sort=sort)
assert the_int is idx
if sort:
tm.assert_index_equal(the_int, idx.sort_values())
else:
assert the_int is idx

# empty intersection: disjoint
empty = idx[:2].intersection(idx[2:], sort=sort)
Expand All @@ -249,3 +258,47 @@ def test_intersection(idx, sort):
# tuples = _index.values
# result = _index & tuples
# assert result.equals(tuples)


def test_intersect_equal_sort():
idx = pd.MultiIndex.from_product([[1, 0], ['a', 'b']])
sorted_ = pd.MultiIndex.from_product([[0, 1], ['a', 'b']])
tm.assert_index_equal(idx.intersection(idx, sort=False), idx)
tm.assert_index_equal(idx.intersection(idx, sort=True), sorted_)


@pytest.mark.parametrize('slice_', [slice(None), slice(0)])
def test_union_sort_other_empty(slice_):
# https://github.com/pandas-dev/pandas/issues/24959
idx = pd.MultiIndex.from_product([[1, 0], ['a', 'b']])

# default, sort=None
other = idx[slice_]
tm.assert_index_equal(idx.union(other), idx)
# MultiIndex does not special case empty.union(idx)
# tm.assert_index_equal(other.union(idx), idx)

# sort=False
tm.assert_index_equal(idx.union(other, sort=False), idx)

# sort=True
result = idx.union(other, sort=True)
expected = pd.MultiIndex.from_product([[0, 1], ['a', 'b']])
tm.assert_index_equal(result, expected)


def test_union_sort_other_incomparable():
# https://github.com/pandas-dev/pandas/issues/24959
idx = pd.MultiIndex.from_product([[1, pd.Timestamp('2000')], ['a', 'b']])

# default, sort=None
result = idx.union(idx[:1])
tm.assert_index_equal(result, idx)

# sort=False
result = idx.union(idx[:1], sort=False)
tm.assert_index_equal(result, idx)

# sort=True
with pytest.raises(TypeError, match='Cannot compare'):
idx.union(idx[:1], sort=True)
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